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Higher - Perimeter. area and volume

infoWhy this? We are teaching this unit so that pupils can calculate areas, perimeters, surface areas and volumes for an increasingly wide range of 2D and 3D shapes, including part-circles, prisms, cylinders, pyramids, cones, spheres and frustums, enabling them to tackle complex, real-life measurement problems accurately

scheduleWhy now? We are teaching it now in Year 10 so that pupils can use these measurement techniques to support their current work in geometry, ratio and problem-solving, particularly in multi-step GCSE questions that involve composite and curved shapes

neurologyYou need to know

  • The area of a compound shape can be found by splitting it into simpler shapes, finding each area, then adding the areas or subtracting unwanted areas.
  • The perimeter of a compound shape is the total length around the outside boundary, including straight sides and any curved edges.
  • The formula for the area of a rectangle is `A = lw`, where `l` is length and `w` is width.
  • The formula for the area of a triangle is `A = \frac{1}{2}bh`, where `b` is the base and `h` is the perpendicular height.
  • The formula for the area of a circle is `A = \pi r^2`, where `r` is the radius.
  • The formula for the circumference of a circle is `C = 2\pi r` or `C = \pi d`, where `d` is the diameter.
  • A semicircle is half of a circle, so its area is `\frac{1}{2}\pi r^2` and its curved edge is `\pi r`.
  • A quarter-circle is one quarter of a circle, so its area is `\frac{1}{4}\pi r^2` and its curved edge is `\frac{1}{2}\pi r`.
  • The volume of any prism is `\text{volume} = \text{area of cross-section} \times \text{length}`.
  • A triangular prism has a triangular cross-section, so its volume is `\frac{1}{2}bh \times \text{length}`.
  • The volume of a cylinder is `V = \pi r^2h`, where `r` is the radius of the circular cross-section and `h` is the height or length of the cylinder.
  • The surface area of a prism is the total area of all its faces, including the two identical end faces and the rectangular side faces.
  • The curved surface area of a cylinder is `2\pi rh`, and the total surface area of a closed cylinder is `2\pi rh + 2\pi r^2`.
  • The length of an arc with angle `\theta` degrees is `\frac{\theta}{360} \times 2\pi r`.
  • The area of a sector with angle `\theta` degrees is `\frac{\theta}{360} \times \pi r^2`.
  • A segment of a circle is the region between a chord and an arc, and its area is found by subtracting the area of the triangle from the area of the sector.
  • The volume of a pyramid is `V = \frac{1}{3} \times \text{area of base} \times \text{perpendicular height}`.
  • The volume of a cone is `V = \frac{1}{3}\pi r^2h`, and the volume of a sphere is `V = \frac{4}{3}\pi r^3`.
  • The surface area of a cone is `\pi r^2 + \pi rl`, where `l` is the slant height, and the surface area of a sphere is `4\pi r^2`.
  • A frustum is made by removing a smaller similar cone or pyramid from a larger cone or pyramid, so its volume is the larger volume minus the smaller volume.

rocket_launchYou must be able to

  • Calculate the area of a compound shape by decomposing it into rectangles, triangles, circles or part-circles and combining the areas accurately.
  • Calculate the perimeter of shapes involving semicircles, quarter-circles or sectors by adding straight lengths and curved arc lengths only on the boundary.
  • Calculate the volume of prisms, including triangular prisms and cylinders, by identifying the cross-section area and multiplying by the length or height.
  • Calculate the surface area of cuboids, triangular prisms and cylinders by finding every face area once and adding them systematically.
  • Calculate the arc length and sector area for any angle by using the fraction `\frac{\theta}{360}` of the full circumference or full circle area.
  • Calculate the area of a circular segment by finding the sector area, finding the associated triangle area, and subtracting the triangle from the sector.
  • Solve problems involving prisms, pyramids, cones and spheres by selecting the correct formula, substituting measurements with consistent units, and giving answers to an appropriate degree of accuracy.
  • Solve surface area and volume problems for compound 3D shapes by splitting them into standard solids or subtracting removed parts such as holes or missing sections.
  • Calculate the volume of a frustum by using similar shapes or by subtracting the volume of the smaller removed cone or pyramid from the original larger solid.


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